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Assuming a ball is shot vertically up in the air from a hole on the ground with the initial velocity of 12 feet per second. The position of the ball in the air after t seconds is represented by the function h(t ) = - 212 + vit + ho where h: height of the ball in the air after t seconds and where t: time and, Vo ho . initial velocity and initial height, respectively. Please find the following: Remind: [how) ) = = velocity measured and [V.) ] = an) = acceleration measured- sec sec a. How long would it take the ball to come back and hit the ground? (Hints: back to ground set h= 0 then solve for t. Throw out negative answer), (Ans :t = 6sec) ? b. What is the function velocity of the ball and what is the velocity of the moment of impact? (ans :V = -4t +12 & Vimpact =-12 ft / sec) c. How long would it take for the ball to reach its maximum height in the air? (3 seconds). Hints: when the ball reaches it maximum height its velocity is zero at the instant then the ball will be falling. Set V = 0 then solve for t. d. What is the velocity of the ball after 2 seconds? (ans : (2) = 4 ft / sec) e. What is the acceleration function of the ball? (ans : A() = -4 f,)