(see the XRD plot for Ge to the right) a) What structure does Germanium have at...

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(see the XRD plot for Ge to the right) a) What structure does Germanium have at room temperature? b) Draw and calculate the surface atomic concentration of the Ge (111) and (220) Intensity (a.u) 20 (111) 30 40 (220) 50 (311) 60 2theta (degrees) c) Using Bragg's Law, calculate the angles in 20 and compare your findings to plotted values. Assume - Cu Ka radiation (2-0.15406 nm), a= 0.5657 nm, and room temperature. (see the XRD plot for Ge to the right) a) What structure does Germanium have at room temperature? b) Draw and calculate the surface atomic concentration of the Ge (111) and (220) Intensity (a.u) 20 (111) 30 40 (220) 50 (311) 60 2theta (degrees) c) Using Bragg's Law, calculate the angles in 20 and compare your findings to plotted values. Assume - Cu Ka radiation (2-0.15406 nm), a= 0.5657 nm, and room temperature. (see the XRD plot for Ge to the right) a) What structure does Germanium have at room temperature? b) Draw and calculate the surface atomic concentration of the Ge (111) and (220) Intensity (a.u) 20 (111) 30 40 (220) 50 (311) 60 2theta (degrees) c) Using Bragg's Law, calculate the angles in 20 and compare your findings to plotted values. Assume - Cu Ka radiation (2-0.15406 nm), a= 0.5657 nm, and room temperature.

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2 m Garmanium 60 has a diamond cubic Cyrstal Structura at rom toppers bre b surface atomic Concentra... View the full answer