Question: Select oneA. The program does not compile because the Scanner input = new Scanner ( System . in ) ; statement is inside the loop.B
Select oneA. The program does not compile because the Scanner input new ScannerSystemin; statement is inside the loop.B The program compiles, but does not run because the Scanner input new ScannerSystemin; statement is inside the loop.C The program compiles and runs, but it is not efficient and unnecessary to execute the Scanner input new ScannerSystemin; statement inside the loop. You should move the statement before the loop.D The program compiles, but does not run because there is not prompting message for entering the input.
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