Question: Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The minimum value is 9 . (Round

 Select the correct choice below and, if necessary, fill in theanswer box to complete your choice. A. The minimum value is 9. (Round to the nearest tenth as needed.) X B. There isno minimum value. Select the correct choice below and, if necessary, fill

Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The minimum value is 9 . (Round to the nearest tenth as needed.) X B. There is no minimum value. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. The maximum value is . (Round to the nearest tenth as needed.) B. There is no maximum value.Find the minimum and maximum values of z = Ex+?1.r. if possible. for the following set of constraints. 4x+3y212 x+3y26 3:204:20 Select the correct choice belowr and. if necessary. fill in the answer box to complete your choice. [:1 A. The minimum value is . {Round to the nearest tenth as needed.) [:1 E. There is no minimum value. Given Z= 6x + 74. Subject to constraints 42+ 34 7, 12 x + 3 7 >6 27,0 , 470 Now. comvent the given inequations jonto equations and plot them on a graph: 42 + 34 = 12, 2+34=6, 250, 4=0. 8 4 3 2 4 S 6 8 The shaded region satisfied by above sme qualities. Here feasible region is unbounded. The common points are given as ( 0 , 4 ) , ( 2 , 4 ) , ( 6,0 ) cornon point TI = 62+74 ( 0 , 4 ) 28 ( 2,4 ) 64 minimum value. ( 6, 0 ) 36 Answer: The minimum value is 64 2 21.3 3Now, solving the equations 42 + By =12 we get 2= 2, 42 They : the intersection point of two straight line Inthegraph is ( 2,4 ). answer A The minimum value is 64 ~ 3 121 1 3 B) there is no maximum value

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