Select the correct equations that show that the primary coil has ten times as many turns as the secondary coil.

NprimaryNsecondary$=$VinputVoutput$=120$V$12$V$=10$NprimaryNsecondary$=$VinputVoutput$=120$V$12$V$=10$NprimaryNsecondary$=$V$2$outputV$2$input$=(12$V$)2(120$V$)2=10$NprimaryNsecondary$=$Voutput$2$Vinput$2=(12$V$)2(120$V$)2=10$NprimaryNsecondary$=$VoutputVinput$=12$V$120$V$=10$NprimaryNsecondary$=$VoutputVinput$=12$V$120$V$=10$NprimaryNsecondary$=$Vinput$$Voutput$=(120$V$)(12$V$)=10$NprimaryNsecondary$=$Vinput$$Voutput$=(120$V$)(12$V$)=10$