Select the FIRST correct reason why the given series converges.

A$.$ Convergent geometric series

B$.$ Convergent $p$ series

C$.$ Comparison $($or Limit Comparison$)$ with a geometric or $p$ series

D$.$ Alternating Series Test

E$.$ None of the above

${\displaystyle \underset{n=1}{\overset{}{}}}\frac{(-1{)}^{n}ln(e^n)}{n^{4}cos(n)}$

${\displaystyle \underset{n=1}{\overset{}{}}}\frac{cos(n)}{ln(2n)}$

${\displaystyle \underset{n=1}{\overset{}{}}}(-1{)}^n\frac{\sqrt[\phantom{2}]{n}}{n+9}$

${\displaystyle \underset{n=1}{\overset{}{}}}\frac{7(4{)}^n}{9^{2n}}$

${\displaystyle \underset{n=1}{\overset{}{}}}\frac{(n+1)(35{)}^n}{6^{2n}}$

${\displaystyle \underset{n=1}{\overset{}{}}}\frac{(-1{)}^n}{7n+2}$