select the following statements that are true.

Any Boolean expression can be implemented with a number of AND gates.

Any Boolean expression can be implemented with a number of NAND gates.

$(\stackrel{}{x}\frac{+}{b}ar(y))*(x+y)$ is equivalent to $xo+y.$

nor $Y)$ is equivalent to $\stackrel{}{x}\frac{*}{b}ar(Y).$

$(x$ nand $Y)$ is equivalent to $\stackrel{}{x}\frac{*}{b}ar(Y).$