Select the integrals that converge

${\displaystyle \underset{-}{\overset{-1}{}}}{e}^{x^2}dx$

${\displaystyle \underset{-}{\overset{-1}{}}}{e}^{\sqrt[3]{x}}dx$

${\displaystyle \underset{1}{\overset{}{}}}{e}^{-\sqrt[\phantom{2}]{x}}dx$

${\displaystyle \underset{-1}{\overset{0}{}}}{e}^{\frac{1}{x}}dx$