Select the statements where the calculation rules are correctly applied. $\underset{\text{x}\text{d}\text{a}\text{r}\text{r}9}{lim}\frac{-8}{(x-9{)}^2}=(\underset{\text{x}\text{d}\text{a}\text{r}\text{r}9}{lim}\frac{-8}{x-9})*(\underset{\text{x}\text{d}\text{a}\text{r}\text{r}9}{lim}\frac{1}{x-9})\underset{x-}{lim}(\frac{(x-4{)}^2}{x-1}{)}^2=(\underset{x-}{lim}(\frac{(x-4{)}^2}{x-1}){)}^2\underset{x}{lim}\frac{x-2}{(x-2{)}^2}=(\underset{x}{lim}x-2)*(\underset{x}{lim}\frac{1}{(x-2{)}^2})\underset{x-}{lim}(\frac{-x-3}{x-1})=\frac{\underset{x-}{lim}(-x-3)}{\underset{x-}{lim}(x-1)}\underset{x}{lim}((x-2)*(x-5){)}^0=(\underset{x}{lim}(x-2)*(x-5){)}^0\underset{x}{lim}(\frac{x^3}{x-3}-\frac{x-7}{x-3})=(\underset{x}{lim}\frac{x^3}{x-3})-(\underset{x}{lim}\frac{x-7}{x-3})$