Semaphore Solution to the Dining Philosophers Problems. Assuming that chopstick$[$i$]$ is on the right$-$hand side of

Philosopher i and chopstick$[($i $+1)\%5]$ is on the left$-$hand side of Philosopher i $,$ USE the approach #$3$ given in PPT Slide $3\mathrm{.}51$ to

RE$-$WRITE the code for Philosopher i given in PPT Slide $3\mathrm{.}50$ to remove its deadlock problem. $($Hint: the SAME piece of code

MUST work for any value of i regardless whether it$$s odd or even.