sentence or two explaining your reasoning or calculations you did in R. 1. A certain electric car company claims publicly that their car batteries will last for at least 300,000 miles. An internal study done by the company showed that the lifespans of their car batteries followed a normal probability distribution with a mean lifespan of 400,000 miles and a standard deviation of 60,000 miles. What percent of their car batteries will fail to meet the public claim of lasting at least 300,000 miles? (Round to the nearest tenth mean = M = 400 000 of a percent.) (a) 2.4% S.d. 660 000 (b) 4.8% 3 P(X 300 ) 00 (c) 5.0% = P(x-> 30-M) = P( (d) 8.4% 9.6% -2 by 2 table 300000 6 300 000 60.000 (00000) P(22-1.67) P(21.67) 60.95254 20.96 26 %