Question: ! ! ! service times m = = m 1 = 1 5 m 2 = 2 0 m 3 = 1 5 ! !

!!!service times m== m1=15
m2=20
m3=15!!! SOLVE ACCORDING TO THIS. AND I NEED THE ANSWER FAST PLEASE. Send MATHEMATICAL Answers .Consider a Jackson network with three service facilities having the parameter values shown below.
\table[[,,,,pij
 !!!service times m== m1=15 m2=20 m3=15!!! SOLVE ACCORDING TO THIS. AND

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