Set up$,$ but do not evaluate, an integral for the length of $y=\sqrt[\phantom{2}]{x+2},1x7$ using,

$($a$)$

$ds=\sqrt[\phantom{2}]{1+[\frac{dy}{dx}{]}^2}dx$

$($b$)$

$ds=\sqrt[\phantom{2}]{1+[\frac{dx}{dy}{]}^2}dy$