Question: Should i use the z-score normalized value to predict the unknown iris plant? for instance, x1 is 0.6 (sepal length) and y1 is -0.6 (sepal
Should i use the z-score normalized value to predict the unknown iris plant? for instance, x1 is 0.6 (sepal length) and y1 is -0.6 (sepal width)
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