Question: Show by universal generalization (twice-applied) that (((C-A)B)(DB))=(B((C-A)D)). Never understood universal generalization, Can someone explain step by step with cases for this problem?
Show by universal generalization (twice-applied) that (((C-A)B)(DB))=(B((C-A)D)). Never understood universal generalization, Can someone explain step by step with cases for this problem?
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