Show $me$ the steps $to$ solve The horizontal rigid bar $is$ supported $by$ the pin connection and two vertical axial bars $(1)$ and $(2)$ that are pinned $at$ both ends $(this$ means they only take $an$ axial force $-no$ shear $or$ moment$).$ A vertical load $is$ applied $as$ shown. The horizontal bar $is$ pinned $atC.$ Find the normal stresses $in(1)$ and $(2)$ and the vertical displacement $atD.$ All horizontal distances are $in$ meters. Lengths, area, and MOE $of$ the two vertical axial bars: $(1)L1=0\mathrm{.}75m,A1=1x10-4m2,E1=150$ GPa, $(2)L2=1\mathrm{.}25m,A2=3x10-4m2,E2=200$GPa.Answers:$1=32\mathrm{.}89$MPa$(C),2=92\mathrm{.}1$MPa$(C),D=0\mathrm{.}329mm$ down. Hint: Once you find the displacement $atBorF,$ set $up$ another similar triangle $to$ get the displacement $atD.$ The horizontal rigid bar is supported by the pin connection and two vertical axial bars $(1)$ and $(2)$

that are pinned at both ends $($this means they only take an axial force $-$ no shear or moment$).$ A

vertical load is applied as shown. The horizontal bar is pinned at $C.$ Find the normal stresses in

$(1)$ and $(2)$ and the vertical displacement at D$.$ All horizontal distances are in meters. Lengths,

area, and MOE of the two vertical axial bars: $(1)L_1=0\mathrm{.}75m,A_1=1{10}^{-4}{m}^2,E,1=150$GPa, $(2)$

$L_2=1\mathrm{.}25m,A_2=3{10}^{-4}{m}^2,E_2=200$GPa. Answers: ${}_1=32\mathrm{.}89$MPa $($C$),{}_2=92\mathrm{.}1$MPa$(C),{}_D=$

$0\mathrm{.}329mm$ down. Hint: Once you find the displacement at $B$ or $F,$ set up another similar triangle

to get the displacement at D$.$