Show me the steps to solve Two solid cylindrical rods $AB$ and $BC$ are welded together at $B$ and loaded as shown. Knowing that the average normal stress must not

exceed $150$ MPa in either rod, determine the smallest allowable values of the diameters $d_1$ and $d_2.$ Take $P=50kN.$

The smallest allowable value of the diameter $d_1$ is

mm $.$

The smallest allowable value of the diameter $d_2$ is

mm

d$1$ is $20\mathrm{.}6$

d$2$ is NOT $23\mathrm{.}2$ or $20\mathrm{.}6$