Question: show steps please 221. Given f'(x) = (x - 3)2(4x + 3) and f(x) = 4(x - 3) [3x - 1], x = = is

 show steps please 221. Given f'(x) = (x - 3)2(4x +

show steps please

3) and f"(x) = 4(x - 3) [3x - 1], x =

221. Given f'(x) = (x - 3)2(4x + 3) and f"(x) = 4(x - 3) [3x - 1], x = = is one of the critical points of f ( x ) . a. Use the first derivative test to determine if there is a max or min or neither for f(x) at x = 4/3 b. Use the 2nd derivative test to determine if there is a max or min or neither for f(x) at x = 4/3

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