Question: Show that an action - value version holds for the action - value form of the T D error t = R t + 1

Show that an action-value version holds for the action-value form of the TD error t=Rt+1+Q(St+1,At+1)-Q(St,At), again assuming that the values don't change from step to step.
 Show that an action-value version holds for the action-value form of

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