Question: Show that if the average depth of an n-node binary search tree is ?(log n) then the height of the tree is O . Next

Show that if the average depth of an n-node binary search tree is ?(log n) then the height of the tree is O. Next demonstrate that this bound is tight: there is a binary search tree with average node depth ?(log n) and height ?(n log n).

V nlogn)

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