Question: Show that in metal cutting when the normal working rake is zero, the ratio of the shear strength of the work material, ts to the

Show that in metal cutting when the normal working rake is zero, the ratio of the shear strength of the work material, ts to the specific cutting energy Ps is given by (Ts/Ps)=[(1-rc)rc/(1+(c)^2)] where u is the coefficient of chip-tool friction, and rc is the cutting ratio

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