Question: Show that the equation 3x + 2 cos x + 5 = 0 has exactly one real root. Find the smallest possible area of an

 Show that the equation 3x + 2 cos x + 5= 0 has exactly one real root. Find the smallest possible areaof an isosceles triangle that is circumscribed about a circle of radiusr. Use the graphs of f, f', and f" to estimate thex-coordinates of the maximum and minimum points and inflection points of f.

COS X 41. f(X) = -TEXST VX? + X + 1 42.f (X) = ex In(x? - 1)20 10 -20 -10 0 1020\ff ( - 1 ) = 3 ( - 1 ) 1.let floc ) = 3se + 2cosxx +s f ( 0 )= 7 ( caso = 4 ) * ( - 3 )

Show that the equation 3x + 2 cos x + 5 = 0 has exactly one real root. Find the smallest possible area of an isosceles triangle that is circumscribed about a circle of radius r. Use the graphs of f, f', and f" to estimate the x-coordinates of the maximum and minimum points and inflection points of f. COS X 41. f(X) = -TEXST VX? + X + 1 42. f (X) = ex In(x? - 1)20 10 -20 -10 0 10 20\ff ( - 1 ) = 3 ( - 1 ) 1. let floc ) = 3se + 2cosxx +s f ( 0 ) = 7 ( caso = 4 ) * ( - 3 ) = - 10028 / Gas ( - 3 ) = 0.9986 As f ( 0 ) > 0 + $ ( - 3 )

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