Question: An irrotational region of two-dimensional flow is formed by superimposing a source of strength m 1 = 2.00 m 2 /s at (x,y) = (0,
An irrotational region of two-dimensional flow is formed by superimposing a source of strength m1= 2.00 m2/s at (x,y) = (0, –1), a sink of strength m2= –1.00 m2/s at (x,y) = (1, –1), and a vortex of strength Γ = 1.50 m2/s at (x,y) = (1,1), where all spatial coordinates are in meters. Calculate the fluid velocity at the point (x,y) = (1,0). In the figure below, m is represented as (V& / L), which can be used to approximate three dimensional line source of length L (perpendicular to the figure plane) and volume flow rate V . (picture is attached)
A long circular cylinder of diameter 2a meters is set horizontally in a steady stream (perpendicular to the cylinder axis) of velocity U m/s. The cylinder is caused to rotate at ω rad/s around its axis. Obtain an expression in terms of ω and U for the ratio of the pressure difference between the top and bottom of the cylinder divided by the dynamic pressure of the stream (i.e., the pressure coefficient difference).
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Answer Lets denote the velocity at 1 0 as V1 0 Velocity due to the source m1 200 m2s at 0 1 Vsource m1 2 1 r where r is the distance from the source t... View full answer
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