Show that there is a number a such that sin(x) = x+1 by filling in the details of the following argument. Define f(x) = sin(x) - x - 1, which is graphed below. Then f(a) < 0 for a = f(b) > 0 for b= -4 -3 -1 x 3 2. 1 0 -2- 1 2 Since f(x) is continuous, by the Intermediate Value Theorem there is a number c, where b