Question: Show the activation frames for the first 10 recursive calls in solving the maze. (0,0), (1,0), (1,1), (1,2), (1,3), (2,3), (3,3), (3,2), (4,2), (5,2), (5,3),

Show the activation frames for the first 10 recursive calls in solving the maze. (0,0), (1,0), (1,1), (1,2), (1,3), (2,3), (3,3), (3,2), (4,2), (5,2), (5,3), (6,3), (7,3), (7,4), (7,5), (8,5) and (9,5) represent the path that solves the maze problem. import java.awt.*; import static GridColors.*; /** Class that solves maze problems with backtracking. */ public class Maze { /** The maze */ private TwoDimGrid maze; public Maze(TwoDimGrid m) { maze = m; } /** Wrapper method. */ public boolean findMazePath() { return findMazePath(0, 0); // (0, 0) is the start point. } /** Attempts to find a path through point (x, y). pre: Possible path cells are in BACKGROUND color; barrier cells are in ABNORMAL color. post: If a path is found, all cells on it are set to the PATH color; all cells that were visited but are not on the path are in the TEMPORARY color. @param x The x-coordinate of current point @param y The y-coordinate of current point @return If a path through (x, y) is found, true; otherwise, false */ public boolean findMazePath(int x, int y) { if (x < 0 || y < 0 || x >= maze.getNCols() || y >= maze.getNRows()) return false; // Cell is out of bounds. else if (!maze.getColor(x, y).equals(BACKGROUND)) return false; // Cell is on barrier or dead end. else if (x == maze.getNCols()  1 && y == maze.getNRows()  1) { maze.recolor(x, y, PATH); // Cell is on path return true; // and is maze exit. } else { // Recursive case. // Attempt to find a path from each neighbor. // Tentatively mark cell as on path.  maze.recolor(x, y, PATH);  if (findMazePath(x  1, y)  || findMazePath(x + 1, y)  || findMazePath(x, y  1)  || findMazePath(x, y + 1 ) ) {  return true;  } else {  maze.recolor(x, y, TEMPORARY); // Dead end.  return false;  } } } } 

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