Simple Linear Regression

PLEASE HELP ME UNDERSTAND HOW SOLVE PROBLEM IF YOU KNOW HOW TO DO SIMPLE LINEAR REGRESSION.

***THE BOTTOM OF SCREENSHOT PICTURE ATTACHED OF THE MULTICHOIC QUES IS WHERE I NEED HELP***

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The average driving distance (yards) and driving accuracy (percent of drives that land in the fairway) for B golfers are recorded in the table to the right. Complete parts a through 3 below. b. Fit the model, part a, to the data using simple linear regression. Give the least squares prediction equation. = 295.7 4 (- 0.8086) x c. lnterpret the estimated y-intercept of the line. Choose the correct answer below. A. For each additional percentage in accuracy, the distance is estimated to change by the value otthe y-intercept. B. For each additional yard in distance, the accuracy is estimated to change by the value of the y-intercept. n\" G. Since a drive with distance 0 yards is outside the range of the sample data, the y-intercept has no practical interpretation. D. Since a drive with 0% accuracy is outside the range of the sample data, the y-intercept has no practical interpretation. d. Interpret the estimated slope of the line. Choose the correct answer below. O A. For each additional yard in distance, the accuracy is estimated to change by the value of the slope. O B. Since a drive with distance 0 yards is outside the range of the sample data, the slope has no practical interpretation. 0 C. For each additional percentage in accuracy, the distance is estimated to change by the value of the slope. O D. Since a drive with 0% accuracy is outside the range of the sample data, the slope has no practical interpretation. Player chtance (yards) Accuracy (7-) 1 316.8 39.2 2 304.1 50.2 3 309.9 42.6 4 312.4 44.1 5 294.1 55.9 6 290.6 62.6 7 296.3 55.7 6 310.7 46.4