Question: Simplify Boolean Algebra Expression to minimum number of literals. 1. A'(A+B) + (B+AA)(A+B') 2. (A + C)(AD + AD') + AC + C 3. A(A

Simplify Boolean Algebra Expression to minimum number of literals.

1. A'(A+B) + (B+AA)(A+B')

2. (A + C)(AD + AD') + AC + C

3. A(A + B'C) + A(B' + C)

4. C + (BC)'

5. (AB)'(A' + B)(B' + B)

I got

1. A'B + BA + A + AB'

2. A + AC + C

3. A(B'C + B' + C)

4. B'

5. A + A'B + A'B'

Are my anwsers correct? If not, what is the anwser?

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