Question: Simplify the following Boolean function to a minimum number of literals using Boolean algebra. F(x,y,z)= x'y'z + xy'+ yz+ xyz' The correct option is F=y+XZ

Simplify the following Boolean function to a minimum number of literals using Boolean algebra. F(x,y,z)= x'y'z + xy'+ yz+ xyz' The correct option is F=y+XZ O F= xy+ZO F= x+Z F= y +z o

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