Question: Simplify this boolean expression: A'B'CD + A'BC'D + A'BCD' + A'BCD + AB'C'D + AB'CD' + AB'CD + ABC'D' + ABC'D + ABCD' + ABCD.

Simplify this boolean expression: A'B'CD + A'BC'D + A'BCD' + A'BCD + AB'C'D + AB'CD' + AB'CD + ABC'D' + ABC'D + ABCD' + ABCD.

and the resulting simplified expression should be equal to AB + BC + CD + AD + AC + BD.

Please simplify it using boolean identities and not karnaugh maps.

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