Since

f$($x$)=$

$515$x

and

g$($x$)=1,$

applying L'Hospital's Rule and finding the resulting limit gives us the following.

lim$$x$$a$$

f$($x$)$g$($x$)$

$=$lim$$x$$a$$

f$($x$)$g$($x$)$

$$lim$$x $0$

ln$(15$x$)$x

$=$lim$$x $0$

$$

$15$x

$1$

$=$lim$$x $0$

$$

$15$x

$=$