Question: Since f'(x) = 8(sec2(x) - 1) and g'(x) = x sec2(x) + tan(x), applying L'Hospital's Rule gives us the following. lim f(x) lim x-a

Since f'(x) = 8(sec2(x) - 1) and g'(x) = x sec2(x) +

Since f'(x) = 8(sec2(x) - 1) and g'(x) = x sec2(x) + tan(x), applying L'Hospital's Rule gives us the following. lim f(x) lim x-a g(x) =lim f'(x) x-a g'(x) 8(tan(x) - x) = lim xox tan(x) 8(sec2(x) - 1) xotx sec2(x) + tan(x) Analyzing this, we see that as x 0+, 8(sec(x) - 1) -> and x sec2(x) + tan(x) -

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