Single$-$phase bridge inverter has $V_d=100V,R=10,L=25mH,$ and $f=50Hz.$ The instantaneous output voltage is: $v_0={\displaystyle \underset{n=1\mathrm{.}3}{\overset{}{}}},5-\frac{4V_s}{n}sin(nt)$

$($a$)$ The amplitudes of the Fourier series terms for the output voltage wave up to the $9$ th order harmonics,

$($b$)$ The amplitudes of the Fourier series terms for the load current wave up to the $9$th order harmonics.

$($c$)$ The output power $P_0.$

$($d$)$ The power factor, PF$.$

$(3$ points$)$

$(3$ points$)$

$(3$ points$)$

$(3$ points$)$

$(3$ points$)$