Question: sin(x) = (2j + 1)! :1m x2H, derive a Taylor series for sin(x2) around x = 0 using (2j 1)! In Python Write a code

sin(x) = (2j + 1)! :1m x2H, derive a Taylor series

sin(x) = (2j + 1)! :1m x2H, derive a Taylor series for sin(x2) around x = 0 using (2j 1)! In Python Write a code which computes the Taylor series of sin(a2) using recursion and a tolerance based while loop approach. On the interval [O, ], plot the semi-log error in your approximation for tolerance values 10-4, 10-6, and 10-8 a. b sin(x) = (2j + 1)! :1m x2H, derive a Taylor series for sin(x2) around x = 0 using (2j 1)! In Python Write a code which computes the Taylor series of sin(a2) using recursion and a tolerance based while loop approach. On the interval [O, ], plot the semi-log error in your approximation for tolerance values 10-4, 10-6, and 10-8 a. b

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