Sketch the$$ graph of a function that is:

a$)$ Differentiable on $(-5,1)$ and $(1,5)$ and not differentiable at $1.$

b$)$ f$\text{'}($x$)<0$ on $(-5,1)$

c$)$ f$"($x$)=0$ on $(-5,1),$ f$"($x$)>0$ on $(1,3),$ f$"($x$)<0$ on $(3,5)$

d$)$ f is continuous at x$=1$

e$)$ f$(-4)=3,$ f$(-1)=-2$

f$)$ Prove that f has one and only one zero on the interval $(-5,1).$