So far progress with the code.

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package esimatepie;

import java.util.Scanner;

/**

* Programmer: Charity Vincent

* Date: 09/28/2017

*/

public class EsimatePie {

/**

* @param args the command line arguments

*/

public static void main(String[] args) {

// TODO code application logic here

Scanner input = new Scanner(System.in);

System.out.print("Enter a value of n: ");

int n = input.nextInt();

System.out.printf("The estimated value of pie using %d terms is %.4f. ", n, pi(n));

}//end main

static double pi(int n)

{

double est_pi = 0;

int i;

for(i=1; i

est_pi += (double)Math.pow(-1, i+1)/(2*i - 1);

est_pi *= 4;

return est_pi;

}

}

3 5 79 11 2i-1 Write a method that returns m(i) for a given i and write a test program that displays the following table 3 1515 201 3.146 3.144 3.1441 3.1436 401 501 3.1433 3.1430 3.1428 .1427 701 801 901 Sample Output: Here is what your output should look like This program calculates the value of pi using the Gregory-Leibniz series 101 201 301 401 501 601 701 801 901 BUILD SUCCESSEUL (total time: 0 seconds) 4.0000 3.1515 3.1466 3.1449 3.1441 3.1436 3.1433 3.1430 3.1428 3.1427