Question: Solution 2 (b) Solving the equationx2+ y2=100, we gety =100 x2. The point(6,8) lies on the upper semicircley =100 x2 and so we consider the

Solution 2 (b) Solving the equationx2+ y2=100, we gety =100 x2. The point(6,8) lies on the upper semicircley =100 x2 and so we consider the functionf(x)=100 x2. Differentiating f using the Chain Rule, we havef(x)=12(100 x2)12ddx=12(100 x2)12=. Sof(6)= and, as in Solution 1, an equation of the tangent is.

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