SOLUTION Let's look at a simple example of power delivered to a resistor. The bulb for an interior light in a car is rated at 15.0 W and SET UP AND SOLVE The electric power consumption of the bulb is 15.0 W. Thus, operates from the car battery voltage of 12.6 V. What is the resistance of the bulb? P =L V2 R , SO R = V (12.6 V)2 15.0 W = 10.60 REFLECT This is the resistance of the light bulb at its operating temperature. When the light first comes on, the filament is cooler and the resistance is lower. Because P = V2 / R, the bulb has a higher rate of electrical energy consumption when it first comes on. Also, because I = V/ R, the current drawn by the bulb is greater when it is cool and R is less. Part A - Practice Problem: What is the resistance of a heating element when the current through it is 1.20 A and it is consuming electrical energy at a rate of 240 W? Express your answer in ohms. AEQ R= Submit Request Answer