Question: Solution + u a r r F y = - 4 0 0 s i n 2 0 N + F x = - 4

Solution
+uarrFy=-400sin20N
+Fx=-400cos20N
{(ubrace((400sin20)(3)ubrace)))):} Explain the
Find the torque around A? why it is a bit more why it is scaler here?
Solution + u a r r F y = - 4 0 0 s i n 2 0 N + F

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