Solve 14 - 17 showing work please

Find the equation of the tangent line to the curve at the given point using implicit differentiation. Trisectrix of Maclaurin x(x2 + y2) = 3x2 -y2 at (1, -1) w 2 -3 -2 2 -2 15. [-/1 Points] DETAILS BERRAPCALCBR7 3.6.051. MY NOTES ASK YOUR TEACHER In the equation, x and y are functions of t. Differentiate with respect to t to find a relation between dx/dt and dy/dt. x6 + y? = 1 O 6x5 0X + 2y y = 1 dt dt 6x5 0X + 2y- = 0 dt dt O 6x5 dx + 2 dy dt dt dt 6x6 CX + 2y2% = 0 dt dt O 6x6 dx + 2yzdy = 1 dt 16. [-/1 Points] DETAILS BERRAPCALCBR7 3.6.053. MY NOTES ASK YOUR TEACHER In the equation, x and y are functions of t. Differentiate with respect to & to find a relation between dx/dt and dy/dt. xy = 30 O x2 0% + 2xy- ay = 0 dt dt O 2xy X + 2x 0 dt dt Ox + 20% = 0 O 2xy dt xy dx + 2xy = 30 Oxy dt dt v.dx + x2ay = 0 O 2y dt 17. [-/1 Points] DETAILS BERRAPCALCBR7 3.6.055. MY NOTES ASK YOUR TEACHER In the equation, x and y are functions of t. Differentiate with respect to t to find a relation between dx/dt and dy/dt. 3x2- 7xy = 12 O 6xx - dx dt dt dt O 6x x - dx +7- ay - dt dt dt O 6x X _ 7VOX _ 7Xy = 0 dt de dt dt O 6x X _ 7dx - 7XY = 0 dt dt O 6XOX + 7ydX + 7xy = 0 dt