Question: solve 4. Here is a modified version of Kadane's Algorithm. Other than the print statements the logic is exactly the same as the regular version,

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4. Here is a modified version of Kadane's Algorithm. Other than the print statements the logic is exactly the same as the regular version, just written differently. function kadane (A) n = length (A) maxoverall = A [0] maxendingati = A [0] for i = 1 to n-1 inclusive: if maxendingati 0: print "A" maxendingati = maxendingati + A[i] else : print "B" maxendingati = A[i] end if if maxendingati maxoverall : print "Y" maxoverall = maxendingati else : print "Z" end if end for end function (a) Suppose we call: kadane ( [3, 4, -1, -10, -2,5,6,-1]) What will the output string be? (b) Suppose we call kadane (A) on an unknown list A of length n. and the final two letters printed are BY. Prove that at the instant that the Y is printed (and before any more code runs) that maxoverall

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