Solve

A circuit with a capacitor (unknown C), a resistor (R = 5.1 9), a switch, and a battery (V = 5.5 V) is created as shown. The capacitor is initially uncharged and the switch is open. R The circuit forms a single closed loop (once the switch is closed), traversing from the negative terminal of the battery through the capacitor C', then through the resistor R, the switch, and back to the positive terminal of the battery. That is, the loop is: battery (negative terminal first) + C R switch battery (negative terminal). x 1) Immediately after the switch is closed, what is the current through the resistor? |=28A 1=0.927A 1=1.08A 1=0.539 A I=0A