Solve a Specific Antiderivative $($aka Initial Value$)$ Problem.

A manufacturer has determined that an employee with $d$ days of production experience will be able to produce items at a rate of

$p(d)=2\mathrm{.}97e^{-0\mathrm{.}11d}(1-e^{-0\mathrm{.}11d}{)}^2$

items per day. If an employee with no experience can produce $20$ items each day, how many items can an employee with $6$ days of experience produce each day? Round your answer to the nearest tenth of an item, if necessary. Note: $p(d)$ is sometimes used in place of $P^{\text{'}}(d)$ for the rate of change as the meaning is the same: $p(d)=P^{\text{'}}(d).$

The production per day function is $P(d)=$

An employee with $6$ days of experience can produce $$ items per day.