solve e taking in mind Modification to problem $1\mathrm{.}7($e$)$: The text gives you two distributed loads, one $6,000$lb load distributed over $8$ feet and one $10,000$lb load distributed over $14$ feet. Just use $6,000$ lb distributed over the whole beam length, in addition to the $3,000$ lb concentrated load.$($e$)$ Use the principle of superposition using :

BEAM OVERHANGING ONE SUPPORT $$ UNIFORMLY DISTRIBUTED LOAD

$R_1=V,=\frac{w}{2l}(l^2-a^2)$

$R_2=V_2+V_3,=\frac{w}{2l}(1+a{)}^2$

BEAM OVERHANGING ONE SUPPORT $$ CONCENTRATED LOAD AT ANY POINT BETWEEN SUPPORTS

$=(V_{\text{m}\text{e}\text{x}}$ when $ab$

Principle of Superposition: The principle of superposition states that when multiple loads act on a structure, the effect of each load can be analyzed separately as if all the other loads were not present. The final solution is obtained by summing up the effects of the individual loadings.

$($e$)$

Modification to problem $1\mathrm{.}7($e$)$: The text gives you two distributed loads, one $6,000$lb load distributed over $8$ feet and one $10,000$lb load distributed over $14$ feet. Just use $6,000lb$ distributed over the whole beam length, in addition to the $3,000lb$ concentrated load.

BEAM OVERHANGING ONE SUPPORT $-$ UNIFORMLY DISTRIBUTED LOAD

$R_1=V_1$dotsdots$=\frac{w}{2l}(l^2-a^2)$

$R_2=V_2+v=\frac{w}{2l}(l+a{)}^2$

BEAM OVERHANGING ONE SUPPORT $$ CONCENTRATED LOAD AT ANY POINT BETWEEN SUPPORTS

$=(V_{\text{m}\text{a}\text{x}}$ when $ab$

Principle of Superposition: The principle of superposition states that when multiple loads act on a structure, the effect of each load can be analyzed separately as if all the other loads were not present. The final solution is obtained by summing up the effects of the individual loadings.