Question: Solve each of the following initial-value problems x 2 y'' + 3xy' + x 2 =x, y(1)=2, y'(1)=1 y'+(1/3)y = 1/3(1-2x)y 4 siny(dy/dx) = cos
Solve each of the following initial-value problems
- x2y'' + 3xy' + x2=x, y(1)=2, y'(1)=1
- y'+(1/3)y = 1/3(1-2x)y4
- siny(dy/dx) = cos y(1-xcosy), Hint: substitute v=1/cosy
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