Question: solve f zt? gin (2a-3/) dz = C) A. = cos (22-3) +C B. cos (22- 3/7) +C . cos (2a2-/?) +C C) D. None

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f zt? gin (2a-3/) dz = C) A. = cos (22-3) +C B. cos (22- 3/7) +C . cos (2a2-/?) +C C) D. None of these. This one can't be done using the method of substitution. E 3cos (2277/7) + C

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