Solve for O2, CO2, and selectivity, please. All other answers are correct.

Methane and oxygen react in the presence of a catalyst to form formaldehyde. In a parallel reaction, methane is oxidized to carbon dioxide and water. CH4+02 HCHO + HO - CH4+202 CO2 + 2HO The feed to the reactor contains equimolar amounts of methane and oxygen. Assume a basis of 100.0 mol feed/s. a. How many degrees of freedom remain for the overall process? 2 b. The fractional conversion of methane is 0.920 and the fractional yield of formaldehyde is 0.855 mol HCHO/mol CH4 fed. What is the composition of the output stream? 0.5 mol% 0 mol% HCHO 42.5 b. The fractional conversion of methane is 0.920 and the fractional yield of formaldehyde is 0.855 mol HCHO/mol CH fed. What is the composition of the output stream? i 0.5 mol% 0 42.5 mol% HCHO 49.5 mol% HO i 4 mol% CH4 c. What is the selectivity (mol HCHO/mol CO) of the process? 12.14 mol HCHO/mol CO 3.5 mol% CO