5 Lt/s water enters a disc-shaped rotor axially as shown in the figure. 8=300 with tangential...

 

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5 Lt/s water enters a disc-shaped rotor axially as shown in the figure. 8=300 with tangential direction from 3 radial channels in the disc at the angle comes out. Cross section of channels 18 mm2 is. a) If the disc is stationary, the torque acting on it b) If the torque resistance is zero, determine the rotational speed of the disc. 8 H 0.5 m Nozzle exit area normal to relative velocity = 18 mm² Q=5 liters/s 5 Lt/s water enters a disc-shaped rotor axially as shown in the figure. 8=300 with tangential direction from 3 radial channels in the disc at the angle comes out. Cross section of channels 18 mm2 is. a) If the disc is stationary, the torque acting on it b) If the torque resistance is zero, determine the rotational speed of the disc. 8 H 0.5 m Nozzle exit area normal to relative velocity = 18 mm² Q=5 liters/s

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SOLUTION This is a problem involving the calculation of torque and rotational speed of a discshaped ... View the full answer