solve in 60 mins thanks

3. 3 points total) A waste air stream from a chemical process flows at the rate of 1.0 m/s at 300 K and 1 atm. containing 7.4% by volume of benzene vapors. It is desired to recover 83% of the benzene in the gas by a three-step process. First, the gas is scrubbed using a non-volatile wash oil to absorb the benzene vapors. Then, the wash oil leaving the absorber is stripped of the benzene by contact with steam at 1 atm and 373 K. The mixture of benzene vapor and steam leaving the stripper will then be condensed. Because of the low solubility of benzene in water, two distinct liquid phases will form and the benzene layer will be recovered by decantation. The aqueous layer will be purified and returned to the process as boiler feed water. The oil leaving the stripper will be cooled to 300 K and returned to the absorber. The following figure is a schematic diagram of the process The wash oil entering the absorber will contain 0.0476 mole fraction of benzene, the pure oil has an average molecular weight of 198. An oil circulation rate at twice the minimum will be used. In the stripper, a steam rate of 1.5 times the minimum will be used. The equilibrium curve for wash oil-benzene solutions for the two temperatures are given in the next two pages. Compute the following The oil-circulation rate in terms of [Kg/s] required for the operation (10 points) b. The steam rate in terms of [Kg/s) required for the operation. (10 points) If the separator has 95% efficiency in benzene removal, calculate the mole fraction of benzene in the benzene product and the mole fraction of benzene in the wastewater stream. (7 points) d. The number of ideal stages in the absorber. (4 points) The number of ideal stages in the stripper. (4 points) C