Question: Solve it like thus Example Find the integral S x+9 x2+18x-9 dx. Solution: Let u = x2 + 18x - 9. Then du = (2x

Solve it like thus

Example Find the integral S x+9 x2+18x-9 dx. Solution: Let u = x2 + 18x - 9. Then du = (2x + 18) d Rewriting the integral: 1 x2+18x-9 (x + 9) dx 1 = x2+ 18x - 9 2 (x + 9) dx After the substitution, we have - S - du. Integrating, we have = Inlul + C Back-substituting, we have = In|x2 + 18x - 9| + C

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