Solve problems 2-8 by referring to Table 2-1.

And please explain the answer to the problem through a simulation model as in the example below.

ex) Simulation by Hand:

Simulation by Hand: 2-8 In the hand simulation of the simple processing system, suppose the drill press is taken down for burn-in maintenance at time 4 minutes, and it takes 4 minutes to do this work and bring it back up; it then stays up for the rest of the 20-minute simulation length. If there's a part in service when the drill press goes down, it just sits there, its processing suspended until the drill press comes back up, when it's resumed and needs just its remaining processing time (its processing does not have to start over from scratch). During the down time, the arrival process of new parts continues without regard to down time. Regard the drill press as being busy when it's down, and define the time in system of a part to include the time it sits in the drill press but not being worked on if it's unlucky enough to be in service when the drill press is taken down. Using the same input data as in Table 2-1, carry out this simulation by hand and note any differences in the output performance measures from the original model. (See Exercise 6-18 for the question of whether this model change induces statistically significant changes in the output performance measures.) Table 2-1. Arrival, Interarrival, and Service Times of Parts (in Minutes) 'Not only should you be sensible about choosing the base time units (for example, for a simulation of 20 years, don't choose seconds as your base units, and for a simulation of two minutes, don't measure time in days), but you should also choose units that avoid both extremely big and extremely tiny time values in the same model since, even with Arena's double-precision arithmetic, the computer might have trouble with round-off error